nameof_module/README.md
2018-03-27 18:16:48 +05:00

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# nameof() c++11
C++ alternative to [nameof](https://docs.microsoft.com/en-us/dotnet/csharp/language-reference/keywords/nameof) operator.
Linux/OSX | Windows
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Used to obtain the simple name of a variable, type, function.
Before, you had to use string literals to refer to definitions, which is brittle when renaming code elements because tools do not know to check these string literals.
A nameof expression has this form:
```cpp
std::cout << NAMEOF(person.Address.zip_code) << std::endl; // prints "zip_code"
```
## Features
* Simple name
* C++11
* Header-only
* Dependency-free
* Compile-time
* Compilation check
## [Example & Key Use Cases](https://github.com/Terik23/nameof/blob/master/example/example.cpp)
* Name of a variable, function and etc
```cpp
NAMEOF(someVar) -> "someVar"
NAMEOF(someVar.SomeField) -> "SomeField"
NAMEOF(someVar.SomeMethod1()) -> "SomeMethod1()"
NAMEOF(&SomeStruct::SomeMethod2) -> "SomeMethod2"
NAMEOF_FUNCTION(someVar.SomeMethod1()) -> "SomeMethod1()"
NAMEOF_FUNCTION(&SomeStruct::SomeMethod2) -> "SomeMethod2"
NAMEOF_VAR(someVar) -> "someVar"
NAMEOF_VAR(someVar.SomeField) -> "SomeField"
```
* Name of type
```cpp
NAMEOF_TYPE(int[]) -> "int[]"
NAMEOF_TYPE(std::string) -> "string"
NAMEOF_TYPE(std::stringgg) -> error namespace "std" has no member "stringgg"
```
* Constexpr
```cpp
void f() {
int i;
constexpr auto constexpr_work_fine = NAMEOF(i); -> "i"
}
```
* Compilation check
```cpp
void f() {
int i;
NAMEOF(i); -> "i"
NAMEOF(iii); -> error identifier "iii" is undefined
NAMEOF_TYPE(std::stringgg) -> error namespace "std" has no member "stringgg"
}
```
* Validate parameters
```cpp
void f(char* s) {
if (s == nullptr)
throw std::invalid_argument(NAMEOF(s));
}
```
* Logging
```cpp
void f() {
Log(NAMEOF(f), " method entry");
}
```
## Remarks
If you need to get the fully-qualified name, you can use the NAMEOF_FULL(). For example:
```cpp
NAMEOF_FULL(someVar.SomeField) -> "someVar.SomeField"
NAMEOF_FULL(&SomeStruct::SomeMethod2) -> "&SomeStruct::SomeMethod2"
NAMEOF_TYPE_FULL(std::string) -> "std::string"
```
## License MIT